If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3j^2+41j-14=0
a = 3; b = 41; c = -14;
Δ = b2-4ac
Δ = 412-4·3·(-14)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1849}=43$$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-43}{2*3}=\frac{-84}{6} =-14 $$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+43}{2*3}=\frac{2}{6} =1/3 $
| -14=v+4+8v | | 6(t-1)=5(t+1) | | 7y+9+90+67=180 | | 6(3b+4)=3(b-6) | | -16=7+3n+1 | | 7(2x+1)=4x+11 | | x^2-8x+12=4x-20 | | 1/2x-2/5=3/4x-5 | | 8k=-48 | | 10+n÷2=20 | | 7y+9+23+46=180 | | 11x-4x+128=11x+80 | | n-(-8)=10 | | -5n+3+4(-2n+3)=41 | | -5n+3+4(-2+3)=41 | | 10x+20=100-x= | | 7y+9+23=180 | | -6x-(29)=(5x)-(7) | | 4+23-2+7y+9=180 | | 5d-8=5(d+2) | | 1.5y+2×=18 | | 107-w=188 | | 17.25=3x+4.75 | | 25=3v-8 | | 9x-11=7x-3=4x+1 | | 3x-15-x=-13+9x-9 | | 7m+7m=0 | | -2÷3n=12 | | w/8+9.4=-3.4 | | -8-3x=8+3x | | 6*9-5+10*9-41+12x+22=180 | | 3-8y=9+4y |